128-[48+6*7-(x/3+15)]=104
cit este x
multumesc


Răspuns :

128-[48+6*7-(x/3+15)]=104
48+42-(x/3+15)=128-104
90-(x/3+15)=24
x/3+15=90-24
x/3+15=66
x/3=66-15
x/3=51
x=51*3
x=153
128-[48+6*7-(x/3+15)]=104
=> 48+42-(x/3+15)=128+104
=> 90-(x/3+15)=24
=> x/3+15 = 90-24
=> x/3+15 = 66
=> x/3 = 66-15
=> x/3 = 51
=> x=51*3
=> x=153

RĂSPUNSUL ESTE x=153 !

Cu plăcere!