din teorema bisectoarei avem
AC/CD=AB/DB
dar CD=BC-DB=6-DB
4/(6-DB)=5/DB
9DB=30
DB=30/9
CD=6-30/9=54-30/9=24/9=8/3
b) ED||AB cu th lui Thales avem
CE/EA=CD/DB
dar si
ΔCED≈ΔCAB si
CE/CA=CD/CB=ED/AB
CE/4=(8/3):6=4/9
CE=16/9
iar EA=4-16/9=20/9
CD/CB=ED/AB
4/9=ED/5
ED=20/9
P(EABD)=30/9+20/9+20/9+5=(70+5.9)/9=115/9