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[3+3×3la 43+(7la 5)la 10 :7la7la2]:[9la22+7 la 1 la 22+15 la n+1:3la n]=

Răspuns :

(3 +3⁴⁴ +7⁵⁰ : 7⁴⁹) : [(3²)²² +7+ 15^n +1 /3^n]=

=(3+3⁴⁴+7):[3⁴⁴ +7+(15^n +1/3^n) ]=

=(3+3⁴⁴ +7): (3⁴⁴+7 +45^2n+1)=

=3 -45^2n=

=3(1-15^2n)