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Calculati media aritmetica si geometrica a numerelor: a=7-radial 13 si b=7+radical 13
va rog


Răspuns :

ma =[7-√ ̅13 + 7+√ ̅13 ] : 2
ma = 14 :2 => ma = 7
-√ ̅13 se simplifica cu +√ ̅13
             ____________  (asta e un radical mai lung, daca nu intelegi :)) )
mg = √ ̅ (7-√ ̅13)(7+√ ̅13)
           _____
mg = √ ̅ 49-13 
mg = √ ̅ 36 => mg = 6
Sper ca te-a ajutat. Si sper ca e corect :))

[tex]\displaystyle a=7- \sqrt{13} \\ \\ b=7+ \sqrt{13} \\ \\ m_a= \frac{a+b}{2} =\frac{7- \sqrt{13}+7+ \sqrt{13} }{2} = \frac{7+7}{2} = \frac{14}{2} =7 \\ \\ m_g= \sqrt{a \cdot b} = \sqrt{(7- \sqrt{13} )(7+ \sqrt{13} )} = \sqrt{49-13} = \sqrt{36} =6[/tex]