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Ati putea sa-mi explicati cum se rezolva..va rog.


Ati Putea Sami Explicati Cum Se Rezolvava Rog class=

Răspuns :

[tex]\frac{x(4x+1)}{6x^2} * \frac{[(3x+1)-(3x-1)]}{(4x^2+4x+1)+(4x^2-4x+1)} \\ \frac{(4x+1)}{6x} * \frac{(3x+1-3x+1)}{8x^2+2} \\ \frac{4x+1}{6x} * \frac{2}{2(4x+1)} \ se \ \ simplifica \ 2 \ si \ 4x+1 \ si \ da \ \\ E(x) = \frac{1}{6x}[/tex]