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rezolva ecuatile
27(n-27)=27
(21-z):21=0


Răspuns :

27(n-27)=27 |:27
n-27=1 |+27
n=28

(21-z):21=0 |x21
21-z=0 |+z
21=z

n-27= 27:27
n-27=1
n=1+27
n=28

21-z=0 X 21
21-z=0
z=21-0
z=21

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