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Se considera functia f;R->R, F(x)=5-x. Calculati f(0)*f(1)*f(2)*...* f(10).

Răspuns :

f(0)=5-0=5
f(1)=5-1=4
f(2)=5-2=3
f(3)=5-3=2
f(4)=5-4=1
f(5)=5-5=0
(0)*f(1)*f(2)*...* f(10)=5*4*3*2*1*0*-1*-2*-3*-4*-5=0


f(0)= 5-0=5
f(1)=5-1=4
f(2)=5-2=3
f(3)=5-3=2
f(4)=5-4=1
f(5)=5-5=0
f(6)=5-6=-1
f(7)=5-7=-2
f(8)=5-8=-3
f(9)=5-9=-4
f(10)=5-10=-5
Suma=0
trebuie sa dai bacul?