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Sa se calculeze f derivat de x pt functiile f:D-R
a) f(x)=x(1+e la x)

b)f(x)=(x la a 2+1) supra x

c) f(x) =3xla a 2 -6x+8 Imi aratati umpic cum se face va rog urgent


Răspuns :

[tex] \frac{x^2+1}{x} = \frac{(x^2+1)'*x-(x^2+1)*x'}{x^2}= \frac{2x^2-x^2-1}{x^2}= \frac{x^2-1}{x^2} [/tex]


[tex](3x^2-6x+8 )'= 6x-6[/tex]


[tex]x* (1+e)^{X} = (x )' * (1+e)^x + x * (1+e)^x = (1+e)^x + x * (1+e)^x* ln 1+e [/tex]